4x^2+.2x+.01=0

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Solution for 4x^2+.2x+.01=0 equation: 



4x^2+.2x+.01=0

We add all the numbers together, and all the variables

4x^2+.2x+0.01=0

a = 4; b = .2; c = +0.01;
Δ = b2-4ac
Δ = .22-4·4·0.01
Δ = -0.12
Delta is less than zero, so there is no solution for the equation

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